1. **State the problem:** Find the value of $x$ when $f(x)$ is 4 more than $g(x)$. 2. **Write the functions:** $$f(x) = 2x + 3$$ $$g(x) = \frac{12 - 3x}{5}$$ 3. **Set up the equation:** We want to find $x$ such that $$f(x) = g(x) + 4$$ 4. **Substitute the expressions:** $$2x + 3 = \frac{12 - 3x}{5} + 4$$ 5. **Clear the fraction by multiplying both sides by 5:** $$5(2x + 3) = 12 - 3x + 20$$ $$10x + 15 = 32 - 3x$$ 6. **Bring all terms involving $x$ to one side and constants to the other:** $$10x + 3x = 32 - 15$$ $$13x = 17$$ 7. **Solve for $x$:** $$x = \frac{17}{13}$$ **Final answer:** $$x = \frac{17}{13}$$