Subjects algebra

Value Of T 68Fac2

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Value Of T 68Fac2


1. **State the problem:** We need to find the value of $t$ given the formula $t = k(4k + n)$ with $k = -2$ and $n = 13$. 2. **Write the formula:** $$t = k(4k + n)$$ 3. **Substitute the values:** $$t = (-2)(4(-2) + 13)$$ 4. **Calculate inside the parentheses:** $$4(-2) = -8$$ $$-8 + 13 = 5$$ 5. **Multiply:** $$t = (-2)(5) = -10$$ **Final answer:** $$t = -10$$