Undefined Values E8Cbc0
1. **State the problem:** We need to find the value(s) of $x$ for which the expression $$\frac{5x+3}{6x(x+1)}$$ is undefined.
2. **Recall the rule:** A rational expression is undefined when its denominator is zero because division by zero is undefined.
3. **Set the denominator equal to zero:**
$$6x(x+1) = 0$$
4. **Solve for $x$:**
Since the product is zero, either factor can be zero:
- $6x = 0 \implies x = 0$
- $x + 1 = 0 \implies x = -1$
5. **Conclusion:** The expression is undefined at $x = 0$ and $x = -1$ because these values make the denominator zero.
**Final answer:** The expression is undefined for $x = 0$ and $x = -1$.