1. The problem asks for the equation of the trend line passing through two given points \((0,8)\) and \((8,4)\).\n\n2. To write the equation in gradient-intercept form \(y = mx + b\), first calculate the slope \(m\) using the formula:\n$$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{4 - 8}{8 - 0} = \frac{-4}{8} = -\frac{1}{2}$$\n\n3. The y-intercept \(b\) is the \(y\)-value when \(x=0\), which is given as 8.\n\n4. Substitute \(m\) and \(b\) into the slope-intercept form:\n$$y = -\frac{1}{2}x + 8$$\n\nTherefore, the equation of the trend line is \(y = -\frac{1}{2}x + 8\).