1. **Problem statement:** A local train travels 50% faster than Rohan's car. Both start from Dadar and reach Borivali, 30 km away, at the same time. The train loses 5 minutes due to stops. Find the speed of the car. 2. **Define variables:** Let the speed of the car be $x$ km/hr. Then, the speed of the train is $1.5x$ km/hr (50% faster). 3. **Time taken by car:** $$\text{Time}_{car} = \frac{30}{x} \text{ hours}$$ 4. **Time taken by train (including stops):** Train runs at $1.5x$ km/hr, so running time without stops: $$\frac{30}{1.5x} = \frac{20}{x} \text{ hours}$$ Train loses 5 minutes = $\frac{5}{60} = \frac{1}{12}$ hours. Total train time: $$\frac{20}{x} + \frac{1}{12}$$ 5. **Since both reach at the same time:** $$\frac{30}{x} = \frac{20}{x} + \frac{1}{12}$$ 6. **Solve for $x$:** Subtract $\frac{20}{x}$ from both sides: $$\frac{30}{x} - \frac{20}{x} = \frac{1}{12}$$ $$\frac{10}{x} = \frac{1}{12}$$ Multiply both sides by $x$ and 12: $$10 \times 12 = x$$ $$x = 120$$ 7. **Answer:** The speed of the car is **120 km/hr**.