Traders Survey 9A7B3A
1. **State the problem:**
We have a survey of traders selling tomatoes and onions with the following information:
- One fourth of traders who sell tomatoes also sell onions.
- Two fifths sell only tomatoes.
- Eleven twentieths sell onions.
- Five traders sell neither tomatoes nor onions.
We need to find:
I. The fraction of traders that sell tomatoes.
II. The total number of traders involved in the survey.
2. **Define variables:**
Let $T$ be the fraction of traders who sell tomatoes.
Let $O$ be the fraction of traders who sell onions.
Let $N$ be the total number of traders.
3. **Translate given information into equations:**
- One fourth of traders who sell tomatoes sell onions means the fraction of traders who sell both tomatoes and onions is $\frac{1}{4}T$.
- Two fifths sell only tomatoes means the fraction who sell tomatoes but not onions is $\frac{2}{5}$.
- Eleven twentieths sell onions means $O = \frac{11}{20}$.
- Five traders sell neither means the fraction who sell neither is $\frac{5}{N}$.
4. **Express the fraction of traders who sell tomatoes:**
The total fraction selling tomatoes is those who sell only tomatoes plus those who sell both:
$$T = \frac{2}{5} + \frac{1}{4}T$$
5. **Solve for $T$:**
$$T - \frac{1}{4}T = \frac{2}{5}$$
$$\frac{3}{4}T = \frac{2}{5}$$
$$T = \frac{2}{5} \times \frac{4}{3} = \frac{8}{15}$$
So, the fraction of traders selling tomatoes is $\frac{8}{15}$.
6. **Find the fraction selling both tomatoes and onions:**
$$\text{Both} = \frac{1}{4}T = \frac{1}{4} \times \frac{8}{15} = \frac{2}{15}$$
7. **Find the fraction selling only onions:**
Since $O = \frac{11}{20}$ and $\text{Both} = \frac{2}{15}$,
$$\text{Only onions} = O - \text{Both} = \frac{11}{20} - \frac{2}{15} = \frac{33}{60} - \frac{8}{60} = \frac{25}{60} = \frac{5}{12}$$
8. **Sum of all fractions:**
$$\text{Only tomatoes} + \text{Only onions} + \text{Both} + \text{Neither} = 1$$
Substitute known values:
$$\frac{2}{5} + \frac{5}{12} + \frac{2}{15} + \frac{5}{N} = 1$$
9. **Find common denominator and sum fractions:**
Common denominator for 5, 12, 15 is 60:
$$\frac{2}{5} = \frac{24}{60}, \quad \frac{5}{12} = \frac{25}{60}, \quad \frac{2}{15} = \frac{8}{60}$$
Sum:
$$\frac{24}{60} + \frac{25}{60} + \frac{8}{60} = \frac{57}{60}$$
10. **Solve for $N$:**
$$\frac{57}{60} + \frac{5}{N} = 1$$
$$\frac{5}{N} = 1 - \frac{57}{60} = \frac{3}{60} = \frac{1}{20}$$
$$N = 5 \times 20 = 100$$
**Final answers:**
- Fraction of traders selling tomatoes: $\frac{8}{15}$.
- Total number of traders surveyed: 100.