Subjects algebra

Thrice Number D81B00

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Thrice Number D81B00


1. **State the problem:** We need to find a number such that when it is multiplied by 3 and then increased by 11, the result is 35. 2. **Set up the equation:** Let the number be $x$. According to the problem, thrice the number increased by 11 equals 35, so we write: $$3x + 11 = 35$$ 3. **Solve the equation:** - Subtract 11 from both sides: $$3x + 11 - 11 = 35 - 11$$ $$3x = 24$$ - Divide both sides by 3: $$x = \frac{24}{3}$$ $$x = 8$$ 4. **Conclusion:** The number is 8.