1. **State the problem:** We need to find the length and width of a tennis court given that the perimeter is 228 feet and the length is 6 feet longer than twice the width. 2. **Set up the equations:** Let the width be $w$ feet. Then the length $l$ is given by: $$l = 2w + 6$$ The perimeter $P$ of a rectangle is: $$P = 2l + 2w$$ Given $P = 228$, substitute $l$: $$228 = 2(2w + 6) + 2w$$ 3. **Solve the equation:** $$228 = 4w + 12 + 2w$$ $$228 = 6w + 12$$ Subtract 12 from both sides: $$228 - 12 = 6w$$ $$216 = 6w$$ Divide both sides by 6: $$w = \frac{216}{6} = 36$$ 4. **Find the length:** $$l = 2w + 6 = 2(36) + 6 = 72 + 6 = 78$$ **Final answer:** The width is 36 feet and the length is 78 feet.