1. Let's denote the three consecutive natural numbers as $n$, $n+1$, and $n+2$. 2. The problem states that their sum is 63, so we write the equation: $$n + (n+1) + (n+2) = 63$$ 3. Simplify the left side by combining like terms: $$3n + 3 = 63$$ 4. Subtract 3 from both sides to isolate terms with $n$: $$3n = 63 - 3$$ $$3n = 60$$ 5. Divide both sides by 3 to solve for $n$: $$n = \frac{60}{3} = 20$$ 6. Now find the three numbers: $$n = 20$$ $$n+1 = 21$$ $$n+2 = 22$$ The three consecutive natural numbers are 20, 21, and 22.