1. The problem is to find the sum of the integers from 1 to 10. 2. We use the formula for the sum of the first $n$ natural numbers: $$S = \frac{n(n+1)}{2}$$ where $n$ is the last number in the sequence. 3. Here, $n = 10$, so substitute into the formula: $$S = \frac{10(10+1)}{2} = \frac{10 \times 11}{2}$$ 4. Calculate the multiplication and division: $$S = \frac{110}{2} = 55$$ 5. Therefore, the sum of the numbers from 1 to 10 is 55.