Square Table Perimeter 391483
1. **State the problem:**
Find the expression for the perimeter of a square table whose area is given by $$9x^4 - 24x^2 + 16$$.
2. **Recall the formulas:**
- Area of a square: $$A = s^2$$ where $$s$$ is the side length.
- Perimeter of a square: $$P = 4s$$.
3. **Find the side length $$s$$:**
Since $$A = s^2 = 9x^4 - 24x^2 + 16$$, we need to find $$s = \sqrt{9x^4 - 24x^2 + 16}$$.
4. **Factor the area expression:**
Notice that $$9x^4 - 24x^2 + 16$$ is a perfect square trinomial:
$$9x^4 - 24x^2 + 16 = (3x^2 - 4)^2$$.
5. **Calculate the side length:**
$$s = \sqrt{(3x^2 - 4)^2} = |3x^2 - 4|$$.
6. **Write the perimeter expression:**
$$P = 4s = 4|3x^2 - 4|$$.
**Final answer:**
$$\boxed{4|3x^2 - 4|}$$