1. **State the problem:** You asked how to get the square root of 3 in the previous question. 2. **Clarification:** Actually, in the previous problem about $f(x) = x^2 + 6x + 5$, we did not calculate or use the square root of 3 anywhere. 3. **Explanation:** The steps involved finding the vertex using the formula $h = -\frac{b}{2a}$ and evaluating $f(h)$ to find the minimum value. No square roots were involved. 4. **Summary:** If you are referring to a different problem or step, please specify, but for the quadratic $x^2 + 6x + 5$, no square root of 3 was used or needed.