1. The problem is to find the value of the square root of 3. 2. The square root of a number $x$ is a value $y$ such that $y^2 = x$. 3. For $\sqrt{3}$, we want a number $y$ such that $y^2 = 3$. 4. Since 3 is not a perfect square, $\sqrt{3}$ is an irrational number approximately equal to 1.732. 5. Therefore, $\sqrt{3} \approx 1.732$. This is the simplest exact form: $\sqrt{3}$.