1. The problem is to understand and work with the function $y = 6 \sqrt{x} + 1$. 2. This function involves a square root, which means $\sqrt{x}$ is defined only for $x \geq 0$. 3. The formula is $y = 6 \sqrt{x} + 1$, where $6$ is multiplied by the square root of $x$, then $1$ is added. 4. To find values of $y$ for specific $x$, substitute $x$ into the formula and simplify. 5. For example, if $x=4$, then $y = 6 \sqrt{4} + 1 = 6 \times 2 + 1 = 12 + 1 = 13$. 6. The graph of this function starts at $y=1$ when $x=0$ and increases as $x$ increases. 7. This function is not defined for negative $x$ because the square root of a negative number is not a real number. 8. The domain is $x \geq 0$ and the range is $y \geq 1$. 9. The function is increasing and concave down because the square root function grows slower as $x$ increases. 10. Final answer: The function is $y = 6 \sqrt{x} + 1$ with domain $x \geq 0$ and range $y \geq 1$.