1. The problem is to solve a system of equations with 1, 2, and 3 unknowns. 2. For 1 unknown, the equation is usually of the form $ax = b$. To solve, divide both sides by $a$ to get $x = \frac{b}{a}$. 3. For 2 unknowns, the system typically looks like: $$\begin{cases} a_1x + b_1y = c_1 \\ a_2x + b_2y = c_2 \end{cases}$$ You can solve this using substitution or elimination methods. 4. For 3 unknowns, the system is: $$\begin{cases} a_1x + b_1y + c_1z = d_1 \\ a_2x + b_2y + c_2z = d_2 \\ a_3x + b_3y + c_3z = d_3 \end{cases}$$ Use substitution, elimination, or matrix methods (like Gaussian elimination). 5. Important rules: - The number of independent equations must be equal to the number of unknowns for a unique solution. - If equations are dependent or inconsistent, solutions may be infinite or none. 6. Example for 2 unknowns: $$\begin{cases} 2x + 3y = 6 \\ x - y = 1 \end{cases}$$ From second equation, $x = y + 1$. Substitute into first: $$2(y + 1) + 3y = 6 \Rightarrow 2y + 2 + 3y = 6 \Rightarrow 5y = 4 \Rightarrow y = \frac{4}{5}$$ Then $x = \frac{4}{5} + 1 = \frac{9}{5}$. 7. This method extends similarly for 3 unknowns but involves more steps. Final answer: Use substitution or elimination methods to solve systems of equations depending on the number of unknowns.