1. The problem states: If \(\text{monopoly}\) is a parallelogram and given expressions are \(x = 3x - 1\) and \(2x - 1\) (assumed as the other expression related to sides or angles), find \(x\). 2. To clarify, since we have an equation \(x = 3x - 1\), we solve this for \(x\): $$x = 3x - 1$$ Move all terms involving \(x\) to one side: $$x - 3x = -1$$ Simplify: $$-2x = -1$$ Divide both sides by \(-2\): $$x = \frac{-1}{-2} = \frac{1}{2}$$ 3. Therefore, the value of \(x\) is \(\frac{1}{2}\). 4. The other expression \(2x - 1\) without a further equation or relation cannot be solved for \(x\) independently, but substituting \(x = \frac{1}{2}\) into \(2x - 1\): $$2 \times \frac{1}{2} - 1 = 1 - 1 = 0$$ This may imply a length or side equals zero depending on context, but from the given info, \(x = \frac{1}{2}\) is the solved value. Final answer: $$x = \frac{1}{2}$$