1. **State the problem:** We need to find the value of $V$ given that $V^4 = 16$. 2. **Recall the formula and rules:** To solve for $V$ when raised to a power, we take the root corresponding to that power. Here, since $V$ is raised to the 4th power, we take the 4th root of both sides: $$V = \pm \sqrt[4]{16}$$ 3. **Calculate the 4th root of 16:** Since $16 = 2^4$, we have $$\sqrt[4]{16} = \sqrt[4]{2^4} = 2$$ 4. **Consider positive and negative roots:** Because raising either $2$ or $-2$ to the 4th power results in $16$, both are solutions. 5. **Final answer:** $$V = \pm 2$$