Solve Square Root 7B3F9F
1. **State the problem:** Solve the equation $w - 3 = \sqrt{5w - 19}$ for $w$.
2. **Understand the equation:** The equation involves a square root. To solve it, we will isolate the square root and then square both sides to eliminate it.
3. **Isolate the square root:** The equation is already isolated as $w - 3 = \sqrt{5w - 19}$.
4. **Square both sides:**
$$ (w - 3)^2 = (\sqrt{5w - 19})^2 $$
$$ (w - 3)^2 = 5w - 19 $$
5. **Expand the left side:**
$$ (w - 3)^2 = w^2 - 6w + 9 $$
6. **Set up the quadratic equation:**
$$ w^2 - 6w + 9 = 5w - 19 $$
7. **Bring all terms to one side:**
$$ w^2 - 6w + 9 - 5w + 19 = 0 $$
$$ w^2 - 11w + 28 = 0 $$
8. **Factor the quadratic:**
$$ (w - 7)(w - 4) = 0 $$
9. **Solve for $w$:**
$$ w = 7 \quad \text{or} \quad w = 4 $$
10. **Check for extraneous solutions:** Substitute back into the original equation.
- For $w=7$:
$$ 7 - 3 = 4 $$
$$ \sqrt{5(7) - 19} = \sqrt{35 - 19} = \sqrt{16} = 4 $$
Valid.
- For $w=4$:
$$ 4 - 3 = 1 $$
$$ \sqrt{5(4) - 19} = \sqrt{20 - 19} = \sqrt{1} = 1 $$
Valid.
**Final answer:**
$$ w = 7 \quad \text{or} \quad w = 4 $$