Solve Rational Exponent 5E1C2C
1. **State the problem:** Solve the equation $$\frac{x^{\frac{3}{2}}}{x-6} = x - 8$$ for $x$.
2. **Rewrite the equation:** Multiply both sides by $x-6$ (assuming $x \neq 6$) to eliminate the denominator:
$$x^{\frac{3}{2}} = (x - 8)(x - 6)$$
3. **Expand the right side:**
$$(x - 8)(x - 6) = x^2 - 6x - 8x + 48 = x^2 - 14x + 48$$
4. **Rewrite the equation:**
$$x^{\frac{3}{2}} = x^2 - 14x + 48$$
5. **Substitute:** Let $y = \sqrt{x}$, so $x = y^2$ and $x^{\frac{3}{2}} = y^3$.
6. **Rewrite in terms of $y$:**
$$y^3 = (y^2)^2 - 14(y^2) + 48 = y^4 - 14y^2 + 48$$
7. **Bring all terms to one side:**
$$0 = y^4 - 14y^2 - y^3 + 48$$
8. **Rearranged:**
$$y^4 - y^3 - 14y^2 + 48 = 0$$
9. **Try to find rational roots:** Test possible roots using Rational Root Theorem (factors of 48).
10. **Test $y=3$:**
$$3^4 - 3^3 - 14 \times 3^2 + 48 = 81 - 27 - 126 + 48 = -24 \neq 0$$
11. **Test $y=4$:**
$$4^4 - 4^3 - 14 \times 4^2 + 48 = 256 - 64 - 224 + 48 = 16 \neq 0$$
12. **Test $y=6$:**
$$6^4 - 6^3 - 14 \times 6^2 + 48 = 1296 - 216 - 504 + 48 = 624 \neq 0$$
13. **Test $y=2$:**
$$2^4 - 2^3 - 14 \times 2^2 + 48 = 16 - 8 - 56 + 48 = 0$$
So, $y=2$ is a root.
14. **Divide polynomial by $(y-2)$:**
Using polynomial division or synthetic division, quotient is:
$$y^3 + y^2 - 12y - 24$$
15. **Factor the cubic:** Try rational roots again.
16. **Test $y=2$ again:**
$$2^3 + 2^2 - 12 \times 2 - 24 = 8 + 4 - 24 - 24 = -36 \neq 0$$
17. **Test $y=-2$:**
$$(-2)^3 + (-2)^2 - 12(-2) - 24 = -8 + 4 + 24 - 24 = -4 \neq 0$$
18. **Test $y=3$:**
$$27 + 9 - 36 - 24 = -24 \neq 0$$
19. **Test $y=-3$:**
$$-27 + 9 + 36 - 24 = -6 \neq 0$$
20. **Use depressed cubic or numerical methods:**
The cubic has no easy rational roots; approximate or use cubic formula.
21. **Approximate roots:** Using numerical methods, roots are approximately $y \approx 4.24$ and $y \approx -2.24$.
22. **Recall $y = \sqrt{x} \geq 0$, so discard negative roots.**
23. **Solutions for $y$:** $y = 2$ and $y \approx 4.24$.
24. **Convert back to $x$:**
$$x = y^2$$
So,
$$x = 2^2 = 4$$
$$x \approx (4.24)^2 = 17.98$$
25. **Check for extraneous solutions:**
- For $x=4$, denominator $x-6 = -2 \neq 0$, check original equation:
$$\frac{4^{3/2}}{4-6} = \frac{8}{-2} = -4$$
Right side: $4 - 8 = -4$ matches.
- For $x \approx 17.98$, denominator $17.98 - 6 = 11.98 \neq 0$, check original equation:
$$\frac{(17.98)^{3/2}}{11.98} \approx \frac{(17.98)^{1.5}}{11.98} \approx \frac{76.2}{11.98} = 6.36$$
Right side: $17.98 - 8 = 9.98$ does not match, so discard.
**Final solution:**
$$\boxed{4}$$