Solve Radical Equation 2F093D
1. Stating the problem: Solve the equation $$\sqrt{3}a - 5 + \sqrt{2}a + 3 + 1 = 0$$ for $a$.
2. Combine like terms: Group the terms involving $a$ and the constants separately.
$$\sqrt{3}a + \sqrt{2}a + (-5 + 3 + 1) = 0$$
3. Simplify the constants:
$$-5 + 3 + 1 = -1$$
So the equation becomes:
$$\sqrt{3}a + \sqrt{2}a - 1 = 0$$
4. Factor out $a$:
$$a(\sqrt{3} + \sqrt{2}) - 1 = 0$$
5. Isolate $a$:
$$a(\sqrt{3} + \sqrt{2}) = 1$$
6. Solve for $a$:
$$a = \frac{1}{\sqrt{3} + \sqrt{2}}$$
7. Rationalize the denominator:
Multiply numerator and denominator by the conjugate $\sqrt{3} - \sqrt{2}$:
$$a = \frac{1}{\sqrt{3} + \sqrt{2}} \times \frac{\sqrt{3} - \sqrt{2}}{\sqrt{3} - \sqrt{2}} = \frac{\sqrt{3} - \sqrt{2}}{(\sqrt{3})^2 - (\sqrt{2})^2}$$
8. Simplify the denominator:
$$(\sqrt{3})^2 - (\sqrt{2})^2 = 3 - 2 = 1$$
9. Final answer:
$$a = \sqrt{3} - \sqrt{2}$$
This is the solution for $a$ in the given equation.