Solve Radical Equation
1. **State the problem:** Solve the equation $$\sqrt{6w + 5} = \sqrt{2w + 8}$$.
2. **Square both sides** to eliminate the square roots:
$$\left(\sqrt{6w + 5}\right)^2 = \left(\sqrt{2w + 8}\right)^2$$
which simplifies to
$$6w + 5 = 2w + 8$$.
3. **Isolate the variable** $w$ by subtracting $2w$ from both sides:
$$6w - 2w + 5 = 8$$
which simplifies to
$$4w + 5 = 8$$.
4. **Subtract 5 from both sides**:
$$4w = 8 - 5$$
which is
$$4w = 3$$.
5. **Divide both sides by 4**:
$$w = \frac{3}{4}$$.
6. **Check for extraneous solutions** by plugging $w = \frac{3}{4}$ back into the original equation:
- Left side: $$\sqrt{6 \times \frac{3}{4} + 5} = \sqrt{\frac{18}{4} + 5} = \sqrt{4.5 + 5} = \sqrt{9.5}$$
- Right side: $$\sqrt{2 \times \frac{3}{4} + 8} = \sqrt{\frac{6}{4} + 8} = \sqrt{1.5 + 8} = \sqrt{9.5}$$
Both sides are equal, confirming the solution.
**Final answer:** $$w = \frac{3}{4}$$.