Solve Quadratic Dd4A39
1. **State the problem:** Solve the equation $ (x+5)(x-5) = x(x-4) + 7 $ for $x$.
2. **Recall the formula:** Use the distributive property (FOIL) to expand both sides.
3. **Expand the left side:**
$$ (x+5)(x-5) = x^2 - 5x + 5x - 25 = x^2 - 25 $$
4. **Expand the right side:**
$$ x(x-4) + 7 = x^2 - 4x + 7 $$
5. **Set the equation:**
$$ x^2 - 25 = x^2 - 4x + 7 $$
6. **Subtract $x^2$ from both sides:**
$$ -25 = -4x + 7 $$
7. **Isolate $x$:**
$$ -25 - 7 = -4x $$
$$ -32 = -4x $$
8. **Divide both sides by $-4$:**
$$ x = \frac{-32}{-4} = 8 $$
**Final answer:**
$$ x = 8 $$