1. The problem is to solve the equation: $$25x^2 = 16$$ 2. The formula used here is to isolate $x$ by taking the square root after dividing both sides by 25. 3. Divide both sides by 25: $$x^2 = \frac{16}{25}$$ 4. Take the square root of both sides: $$x = \pm \sqrt{\frac{16}{25}}$$ 5. Simplify the square root: $$x = \pm \frac{4}{5}$$ 6. Therefore, the solutions are: $$x = \frac{4}{5} \text{ or } x = -\frac{4}{5}$$ This means $x$ can be either positive four-fifths or negative four-fifths to satisfy the equation.