Subjects algebra

Solve Quadratic 281C70

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Solve Quadratic 281C70


1. The problem is to solve the equation $$6x - 48x^2 = 0$$ and understand how $$x = 2$$ is a solution. 2. Start by factoring the equation: $$6x - 48x^2 = 0$$ Factor out the common term $$6x$$: $$6x(1 - 8x) = 0$$ 3. According to the zero product property, if $$ab = 0$$, then either $$a = 0$$ or $$b = 0$$. 4. Set each factor equal to zero: $$6x = 0 \implies x = 0$$ $$1 - 8x = 0 \implies 8x = 1 \implies x = \frac{1}{8}$$ 5. The solutions to the equation are $$x = 0$$ and $$x = \frac{1}{8}$$. 6. The value $$x = 2$$ is not a solution to the original equation. 7. If you meant a different equation or step, please clarify. Final answer: $$x = 0$$ or $$x = \frac{1}{8}$$.