Solve Proportion 73C7D7
1. **State the problem:** Solve for $x$ in the proportion $\frac{7x+1}{2x+3} = \frac{10}{3}$.
2. **Formula and rule:** When two ratios are equal, their cross products are equal. So, $$(7x+1) \times 3 = (2x+3) \times 10$$
3. **Cross multiply:**
$$3(7x+1) = 10(2x+3)$$
4. **Expand both sides:**
$$21x + 3 = 20x + 30$$
5. **Isolate $x$:**
Subtract $20x$ from both sides:
$$21x - 20x + 3 = 30$$
$$x + 3 = 30$$
6. **Solve for $x$:**
Subtract 3 from both sides:
$$x = 30 - 3$$
$$x = 27$$
**Final answer:** $x = 27$