1. **State the problem:** Solve the system of equations: $$3x - 8y = 24$$ $$y = x - 8$$ 2. **Substitute the expression for $y$ from the second equation into the first:** $$3x - 8(x - 8) = 24$$ 3. **Distribute $-8$ inside the parentheses:** $$3x - 8x + 64 = 24$$ 4. **Combine like terms:** $$-5x + 64 = 24$$ 5. **Isolate $x$ by subtracting 64 from both sides:** $$-5x = 24 - 64$$ $$-5x = -40$$ 6. **Divide both sides by $-5$ to solve for $x$:** $$x = \frac{-40}{-5} = 8$$ 7. **Substitute $x = 8$ back into the second equation to find $y$:** $$y = 8 - 8 = 0$$ **Final answer:** $$x = 8, \quad y = 0$$