1. **State the problem:** Solve the system of linear equations: $$0.08x + 0.15y = -0.76$$ $$-0.7x + 0.3y = 0.2$$ 2. **Formula and method:** We will use the method of elimination or substitution to find $x$ and $y$. 3. **Elimination method:** Multiply the first equation by 7 to align coefficients of $x$: $$7 \times (0.08x + 0.15y) = 7 \times (-0.76)$$ $$0.56x + 1.05y = -5.32$$ 4. Now add this to the second equation multiplied by 0.8 to align coefficients of $x$: $$0.8 \times (-0.7x + 0.3y) = 0.8 \times 0.2$$ $$-0.56x + 0.24y = 0.16$$ 5. Add the two new equations: $$(0.56x - 0.56x) + (1.05y + 0.24y) = -5.32 + 0.16$$ $$0 + 1.29y = -5.16$$ 6. Solve for $y$: $$y = \frac{-5.16}{1.29} = -4$$ 7. Substitute $y = -4$ into the first original equation: $$0.08x + 0.15(-4) = -0.76$$ $$0.08x - 0.6 = -0.76$$ $$0.08x = -0.76 + 0.6 = -0.16$$ 8. Solve for $x$: $$x = \frac{-0.16}{0.08} = -2$$ **Final answer:** $$x = -2, \quad y = -4$$