Subjects algebra

Solve Linear Fraction

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Solve Linear Fraction


1. **Stating the problem:** Solve the equation $$\frac{3y - 2}{8} - \frac{4}{3} = \frac{y}{2} - \frac{11}{24}.$$\n\n2. **Rewrite the equation for clarity:** $$\frac{3y - 2}{8} - \frac{4}{3} = \frac{y}{2} - \frac{11}{24}.$$\n\n3. **Find the least common denominator (LCD) for all fractions:** The denominators are 8, 3, 2, and 24. The LCD is 24.\n\n4. **Multiply every term by 24 to clear denominators:**\n$$24 \times \frac{3y - 2}{8} - 24 \times \frac{4}{3} = 24 \times \frac{y}{2} - 24 \times \frac{11}{24}.$$\n\n5. **Simplify each multiplication:**\n- $$24 \times \frac{3y - 2}{8} = 3 \times (3y - 2) = 9y - 6,$$\n- $$24 \times \frac{4}{3} = 8 \times 4 = 32,$$\n- $$24 \times \frac{y}{2} = 12y,$$\n- $$24 \times \frac{11}{24} = 11.$$\n\n6. **Substitute these back into the equation:**\n$$9y - 6 - 32 = 12y - 11.$$\n\n7. **Combine like terms on the left:**\n$$9y - 38 = 12y - 11.$$\n\n8. **Bring variables and constants to one side:**\n$$9y - 12y = -11 + 38,$$\n$$-3y = 27.$$\n\n9. **Solve for $$y$$:**\n$$y = \frac{27}{-3} = -9.$$\n\n**Final answer:** $$y = -9.$$