Solve Linear Equation C2437C
1. **State the problem:** Solve the equation $3y + 15 = 5y + 1$ for $y$.
2. **Write down the equation:**
$$3y + 15 = 5y + 1$$
3. **Goal:** Isolate $y$ on one side of the equation.
4. **Subtract $3y$ from both sides to get all $y$ terms on the right:**
$$15 = 5y - 3y + 1$$
$$15 = 2y + 1$$
5. **Subtract 1 from both sides to isolate the term with $y$:**
$$15 - 1 = 2y$$
$$14 = 2y$$
6. **Divide both sides by 2 to solve for $y$:**
$$y = \frac{14}{2}$$
$$y = 7$$
**Final answer:** $y = 7$