Subjects algebra

Solve Linear Equation C2437C

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Solve Linear Equation C2437C


1. **State the problem:** Solve the equation $3y + 15 = 5y + 1$ for $y$. 2. **Write down the equation:** $$3y + 15 = 5y + 1$$ 3. **Goal:** Isolate $y$ on one side of the equation. 4. **Subtract $3y$ from both sides to get all $y$ terms on the right:** $$15 = 5y - 3y + 1$$ $$15 = 2y + 1$$ 5. **Subtract 1 from both sides to isolate the term with $y$:** $$15 - 1 = 2y$$ $$14 = 2y$$ 6. **Divide both sides by 2 to solve for $y$:** $$y = \frac{14}{2}$$ $$y = 7$$ **Final answer:** $y = 7$