Subjects algebra

Solve Linear Equation 911B98

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Solve Linear Equation 911B98


1. **State the problem:** Forty-three less than twice a number $n$ is 5 more than the number $n$. We need to find the value of $n$. 2. **Write the equation:** "Forty-three less than twice a number $n$" means $2n - 43$. "Is 5 more than the number $n$" means $n + 5$. So, the equation is: $$2n - 43 = n + 5$$ 3. **Solve the equation:** Subtract $n$ from both sides: $$2n - n - 43 = 5$$ Simplify: $$n - 43 = 5$$ Add 43 to both sides: $$n = 5 + 43$$ $$n = 48$$ 4. **Answer:** The number $n$ is 48.