Subjects algebra

Solve Linear Equation 72F3C5

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Solve Linear Equation 72F3C5


1. **State the problem:** Solve the equation $$\frac{9}{4}y - 12 = \frac{1}{4}y - 4$$ for $y$. 2. **Write down the equation:** $$\frac{9}{4}y - 12 = \frac{1}{4}y - 4$$ 3. **Isolate the variable terms on one side:** Subtract $\frac{1}{4}y$ from both sides: $$\frac{9}{4}y - \frac{1}{4}y - 12 = -4$$ 4. **Simplify the left side:** $$\left(\frac{9}{4} - \frac{1}{4}\right)y - 12 = -4$$ $$\frac{8}{4}y - 12 = -4$$ $$2y - 12 = -4$$ 5. **Isolate $2y$ by adding 12 to both sides:** $$2y = -4 + 12$$ $$2y = 8$$ 6. **Solve for $y$ by dividing both sides by 2:** $$y = \frac{8}{2}$$ $$y = 4$$ **Final answer:** $$y = 4$$