Solve Linear Equation 72F3C5
1. **State the problem:** Solve the equation $$\frac{9}{4}y - 12 = \frac{1}{4}y - 4$$ for $y$.
2. **Write down the equation:** $$\frac{9}{4}y - 12 = \frac{1}{4}y - 4$$
3. **Isolate the variable terms on one side:** Subtract $\frac{1}{4}y$ from both sides:
$$\frac{9}{4}y - \frac{1}{4}y - 12 = -4$$
4. **Simplify the left side:**
$$\left(\frac{9}{4} - \frac{1}{4}\right)y - 12 = -4$$
$$\frac{8}{4}y - 12 = -4$$
$$2y - 12 = -4$$
5. **Isolate $2y$ by adding 12 to both sides:**
$$2y = -4 + 12$$
$$2y = 8$$
6. **Solve for $y$ by dividing both sides by 2:**
$$y = \frac{8}{2}$$
$$y = 4$$
**Final answer:** $$y = 4$$