Solve Linear 6B70Da
1. **State the problem:** Solve the equation $q - 12 = 3q + 6$ for $q$.
2. **Write down the equation:**
$$q - 12 = 3q + 6$$
3. **Goal:** Isolate $q$ on one side of the equation.
4. **Step 1: Move all terms involving $q$ to one side.**
Subtract $q$ from both sides:
$$q - 12 - q = 3q + 6 - q$$
Simplifies to:
$$-12 = 2q + 6$$
5. **Step 2: Move constants to the other side.**
Subtract 6 from both sides:
$$-12 - 6 = 2q + 6 - 6$$
Simplifies to:
$$-18 = 2q$$
6. **Step 3: Solve for $q$.**
Divide both sides by 2:
$$q = \frac{-18}{2}$$
Simplifies to:
$$q = -9$$
7. **Final answer:**
$$\boxed{q = -9}$$
**Explanation:** We rearranged the equation to isolate $q$ by moving all $q$ terms to one side and constants to the other, then divided to solve for $q$.