Solve Inequality 3385B4
1. **State the problem:** Solve the inequality $8 < 2 - 2(3x - 1) + \frac{4}{5}x$.
2. **Apply distributive property:** Expand $-2(3x - 1)$ to get $-6x + 2$.
3. **Rewrite the inequality:**
$$8 < 2 - 6x + 2 + \frac{4}{5}x$$
4. **Combine like terms on the right side:**
$$8 < 4 - 6x + \frac{4}{5}x$$
5. **Isolate variable terms:** Subtract 4 from both sides:
$$8 - 4 < -6x + \frac{4}{5}x$$
$$4 < -6x + \frac{4}{5}x$$
6. **Combine the $x$ terms:**
$$-6x + \frac{4}{5}x = -\frac{30}{5}x + \frac{4}{5}x = -\frac{26}{5}x$$
So the inequality is:
$$4 < -\frac{26}{5}x$$
7. **Solve for $x$:** Divide both sides by $-\frac{26}{5}$, remembering to reverse the inequality sign because dividing by a negative number flips the inequality:
$$x < \frac{4}{-\frac{26}{5}}$$
$$x < 4 \times -\frac{5}{26}$$
$$x < -\frac{20}{26}$$
8. **Simplify the fraction:**
$$x < -\frac{10}{13}$$
**Final answer:**
$$x < -\frac{10}{13}$$