1. **State the problem:** Solve the equation $$\frac{g+3}{g-2} = \frac{56}{21}$$ for $g$. 2. **Use the cross-multiplication rule:** For two fractions equal to each other, $$\frac{a}{b} = \frac{c}{d}$$, cross multiply to get $$a \times d = b \times c$$. 3. **Apply cross multiplication:** $$ (g+3) \times 21 = (g-2) \times 56 $$ 4. **Expand both sides:** $$ 21g + 63 = 56g - 112 $$ 5. **Bring all terms involving $g$ to one side and constants to the other:** $$ 21g - 56g = -112 - 63 $$ $$ -35g = -175 $$ 6. **Divide both sides by -35 to solve for $g$:** $$ g = \frac{-175}{-35} = 5 $$ 7. **Final answer:** $$ g = 5 $$ This completes the solution for the first problem.