Solve Fraction Equation E6Ec51
1. **State the problem:** Solve the equation $$\frac{n+6}{10} + \frac{2n}{20} = \frac{6}{3n}$$ for $n$.
2. **Identify the formula and rules:** To solve this equation, we need to find a common denominator and clear fractions by multiplying both sides by the least common denominator (LCD).
3. **Find the LCD:** The denominators are 10, 20, and $3n$. The LCD is $60n$.
4. **Multiply both sides by $60n$ to clear denominators:**
$$60n \times \frac{n+6}{10} + 60n \times \frac{2n}{20} = 60n \times \frac{6}{3n}$$
5. **Simplify each term:**
- $60n \times \frac{n+6}{10} = 6n(n+6)$
- $60n \times \frac{2n}{20} = 6n \times 2n = 12n^2$
- $60n \times \frac{6}{3n} = 20 \times 6 = 120$
6. **Rewrite the equation:**
$$6n(n+6) + 12n^2 = 120$$
7. **Expand and simplify:**
$$6n^2 + 36n + 12n^2 = 120$$
$$18n^2 + 36n = 120$$
8. **Bring all terms to one side:**
$$18n^2 + 36n - 120 = 0$$
9. **Divide entire equation by 6 to simplify:**
$$3n^2 + 6n - 20 = 0$$
10. **Use quadratic formula:**
$$n = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$ where $a=3$, $b=6$, $c=-20$.
11. **Calculate discriminant:**
$$\Delta = 6^2 - 4 \times 3 \times (-20) = 36 + 240 = 276$$
12. **Calculate roots:**
$$n = \frac{-6 \pm \sqrt{276}}{6} = \frac{-6 \pm 2\sqrt{69}}{6} = \frac{-3 \pm \sqrt{69}}{3}$$
13. **Final solutions:**
$$n = \frac{-3 + \sqrt{69}}{3} \quad \text{or} \quad n = \frac{-3 - \sqrt{69}}{3}$$