1. The problem asks to solve for $y$ in the equation $$8x - 4y = -16$$ and express it in slope-intercept form, which is $$y = mx + b$$ where $m$ is the slope and $b$ is the y-intercept. 2. Start by isolating the $y$ term. Subtract $8x$ from both sides: $$-4y = -8x - 16$$ 3. Next, divide every term by $-4$ to solve for $y$: $$y = \frac{-8x}{-4} + \frac{-16}{-4}$$ 4. Simplify the fractions: $$y = 2x + 4$$ 5. So, the slope-intercept form is $$y = 2x + 4$$ meaning the slope $m = 2$ and the y-intercept $b = 4$. Final answer: $$y = 2x + 4$$