1. The problem involves solving the equation $$\frac{9\pi}{3^\circ c} = \frac{3^\circ c + y}{41^\circ c + y} = 2^\circ c$$. 2. First, clarify the equation and variables. It appears to be a proportion or equality involving temperatures and a variable $y$. 3. Assuming the equation to solve is $$\frac{3^\circ c + y}{41^\circ c + y} = 2^\circ c$$, we want to find $y$. 4. Use the cross-multiplication method for proportions: $$3^\circ c + y = 2^\circ c \times (41^\circ c + y)$$. 5. Expand the right side: $$3 + y = 2 \times 41 + 2y$$ (dropping the degree symbol for calculation). 6. Simplify: $$3 + y = 82 + 2y$$. 7. Rearrange terms to isolate $y$: $$3 - 82 = 2y - y$$. 8. Calculate: $$-79 = y$$. 9. Therefore, the solution is $$y = -79$$. 10. This means the variable $y$ must be -79 to satisfy the equation.