Solve Cubic Eq 0D3Ce2
1. **State the problem:** Solve the equation $n \times n \times n = n + n + n$.
2. **Rewrite the equation:** The left side is $n^3$ and the right side is $3n$, so the equation becomes:
$$n^3 = 3n$$
3. **Bring all terms to one side:**
$$n^3 - 3n = 0$$
4. **Factor the equation:**
$$n(n^2 - 3) = 0$$
5. **Set each factor equal to zero:**
- $n = 0$
- $n^2 - 3 = 0$
6. **Solve for $n$:**
- From $n = 0$, we get $n = 0$
- From $n^2 - 3 = 0$, we get $n^2 = 3$, so $n = \pm \sqrt{3}$
7. **Final answer:**
$$n = 0, \sqrt{3}, -\sqrt{3}$$
These are the values of $n$ that satisfy the original equation.