1. **State the problem:** Solve the equation $b \times b \times b = b + b + b$ for $b$. 2. **Rewrite the equation:** The left side is $b^3$ and the right side is $3b$, so the equation becomes: $$b^3 = 3b$$ 3. **Bring all terms to one side:** $$b^3 - 3b = 0$$ 4. **Factor the equation:** $$b(b^2 - 3) = 0$$ 5. **Set each factor equal to zero:** - $b = 0$ - $b^2 - 3 = 0$ 6. **Solve for $b$:** - From $b = 0$, we have $b = 0$ - From $b^2 - 3 = 0$, add 3 to both sides: $$b^2 = 3$$ Take the square root: $$b = \pm \sqrt{3}$$ 7. **Final solutions:** $$b = 0, \quad b = \sqrt{3}, \quad b = -\sqrt{3}$$ These are the values of $b$ that satisfy the original equation.