1. **State the problem:** Solve for all values of $c$ such that $5 = \left| \frac{c}{3} \right|$. 2. **Recall the definition of absolute value:** For any real number $x$, $|x| = a$ means $x = a$ or $x = -a$ where $a \geq 0$. 3. **Apply this to the equation:** $$\left| \frac{c}{3} \right| = 5 \implies \frac{c}{3} = 5 \text{ or } \frac{c}{3} = -5$$ 4. **Solve each equation for $c$:** - If $\frac{c}{3} = 5$, then multiply both sides by 3: $$c = 5 \times 3 = 15$$ - If $\frac{c}{3} = -5$, then multiply both sides by 3: $$c = -5 \times 3 = -15$$ 5. **Final answer:** $$c = 15 \text{ or } c = -15$$ These are the simplest forms of $c$ that satisfy the original equation.