1. Let's verify the solution to the inequality $14x + 2 > 26x + 46$. 2. Start by subtracting $26x$ and $46$ from both sides: $$14x + 2 - 26x - 46 > 0$$ which simplifies to $$-12x - 44 > 0$$ 3. Add $44$ to both sides: $$-12x > 44$$ 4. Divide both sides by $-12$. Remember, dividing by a negative number reverses the inequality: $$x < -\frac{44}{12} = -\frac{11}{3} \approx -3.67$$ 5. The original solution $x \leq 4$ is incorrect. The correct solution is $x < -\frac{11}{3}$. 6. For the taxi problem: Carissa has $25$ total, with a flat fee of $5$ and $2.50$ per km. 7. Subtract the flat fee: $$25 - 5 = 20$$ 8. Divide by the per km charge: $$\frac{20}{2.5} = 8$$ 9. So, Carissa can travel up to $8$ kilometers. 10. The algebraic expression for the taxi fare is: $$5 + 2.5p$$ where $p$ is the distance in kilometers. 11. The solution and explanation for Khiara saving money is correct. 12. The linear pattern with equation $y = -2x + 14$ matches the table values and the calculation for $x = -10$ yielding $y = 34$ is correct. 13. The algebraic expressions and calculations for the coach bus company cost are correct. 14. Summary: The only incorrect part is the inequality solution; it should be $x < -\frac{11}{3}$, not $x \leq 4$. All other answers and explanations are correct.