1. The problem is to find the slope of a line using the rise over run method. 2. "Rise" is the vertical change between two points on the line, calculated as $\text{rise} = y_2 - y_1$. 3. "Run" is the horizontal change between two points, calculated as $\text{run} = x_2 - x_1$. 4. The slope $m$ is found by dividing the rise by the run: $$m = \frac{\text{rise}}{\text{run}} = \frac{y_2 - y_1}{x_2 - x_1}.$$ 5. To apply this, select two points on the line: for example, $(x_1,y_1) = (1,3)$ and $(x_2,y_2) = (4,11)$. 6. Calculate rise: $11 - 3 = 8$. 7. Calculate run: $4 - 1 = 3$. 8. Compute slope: $$m = \frac{8}{3}.$$ This means the line rises 8 units for every 3 units it moves horizontally. 9. The final answer is the slope $m = \frac{8}{3}$, which indicates that for each increase of 3 units in $x$, $y$ increases by 8 units.