Simultaneous Equations Dc3Db3
1. **Problem:** Solve the simultaneous equations:
y + x = 3
and
y^2 - x^2 = 5.
2. **Formula and rules:**
- From the first equation, express y in terms of x: $$y = 3 - x$$.
- Substitute into the second equation: $$y^2 - x^2 = 5$$.
- Recall the identity: $$a^2 - b^2 = (a - b)(a + b)$$.
3. **Substitution and simplification:**
Substitute $$y = 3 - x$$ into $$y^2 - x^2 = 5$$:
$$ (3 - x)^2 - x^2 = 5 $$
Expand $$ (3 - x)^2 $$:
$$ 9 - 6x + x^2 - x^2 = 5 $$
Simplify:
$$ 9 - 6x = 5 $$
4. **Solve for x:**
$$ 9 - 6x = 5 $$
$$ -6x = 5 - 9 $$
$$ -6x = -4 $$
$$ x = \frac{-4}{-6} = \frac{2}{3} $$
5. **Find y:**
Using $$ y = 3 - x $$:
$$ y = 3 - \frac{2}{3} = \frac{9}{3} - \frac{2}{3} = \frac{7}{3} $$
6. **Final answer:**
$$ x = \frac{2}{3}, \quad y = \frac{7}{3} $$
This corresponds to approximately $$ x = 0.67, y = 2.33 $$.
**Note:** The closest option given is x = 1½, y = 2½, but the exact solution is as above.