1. **Problem Statement:** Solve the simultaneous equations from Q1 part a): $$4x + 6y = 16$$ $$x + 2y = 5$$ 2. **Method:** We will use substitution or elimination to solve for $x$ and $y$. Here, elimination is straightforward. 3. **Step 1:** Multiply the second equation by 4 to align coefficients of $x$: $$4(x + 2y) = 4 \times 5 \Rightarrow 4x + 8y = 20$$ 4. **Step 2:** Subtract the first equation from this new equation: $$ (4x + 8y) - (4x + 6y) = 20 - 16 $$ $$ 4x + 8y - 4x - 6y = 4 $$ $$ 2y = 4 $$ 5. **Step 3:** Solve for $y$: $$ y = \frac{4}{2} = 2 $$ 6. **Step 4:** Substitute $y=2$ back into the second original equation: $$ x + 2(2) = 5 $$ $$ x + 4 = 5 $$ $$ x = 5 - 4 = 1 $$ 7. **Step 5:** Verify by substituting $x=1$, $y=2$ into the first equation: $$ 4(1) + 6(2) = 4 + 12 = 16 $$ This matches the right side, so the solution is correct. **Final answer:** $$ x = 1, \quad y = 2 $$