Simplify Roots 1703C4
1. Simplify $\sqrt{12}$.
We know $12 = 4 \times 3$ and $\sqrt{4} = 2$.
So, $\sqrt{12} = \sqrt{4 \times 3} = \sqrt{4} \times \sqrt{3} = 2\sqrt{3}$.
2. Simplify $\sqrt{98}$.
Since $98 = 49 \times 2$ and $\sqrt{49} = 7$,
$\sqrt{98} = \sqrt{49 \times 2} = 7\sqrt{2}$.
3. Simplify $\sqrt{363}$.
Factor 363: $363 = 121 \times 3$ and $\sqrt{121} = 11$.
So, $\sqrt{363} = 11\sqrt{3}$.
4. Simplify $\sqrt{180}$.
$180 = 36 \times 5$ and $\sqrt{36} = 6$.
Thus, $\sqrt{180} = 6\sqrt{5}$.
5. Simplify $\sqrt{250}$.
$250 = 25 \times 10$ and $\sqrt{25} = 5$.
So, $\sqrt{250} = 5\sqrt{10}$.
6. Simplify $\sqrt[4]{48}$.
$48 = 16 \times 3$ and $\sqrt[4]{16} = 2$ because $2^4=16$.
Therefore, $\sqrt[4]{48} = 2\sqrt[4]{3}$.
7. Simplify $\sqrt[5]{486}$.
$486 = 243 \times 2$ and $243 = 3^5$.
So, $\sqrt[5]{486} = \sqrt[5]{3^5 \times 2} = 3\sqrt[5]{2}$.
8. Simplify $\sqrt{4x^2y^3}$.
$\sqrt{4} = 2$, $\sqrt{x^2} = x$ (since variables positive), and $\sqrt{y^3} = y\sqrt{y}$.
So, $\sqrt{4x^2y^3} = 2x y \sqrt{y}$.
9. Simplify $\sqrt{289a^4b^2}$.
$\sqrt{289} = 17$, $\sqrt{a^4} = a^2$, $\sqrt{b^2} = b$.
Thus, $\sqrt{289a^4b^2} = 17 a^2 b$.
10. Simplify $\sqrt{54x^3y^6}$.
$54 = 9 \times 6$, $\sqrt{9} = 3$.
$\sqrt{x^3} = x \sqrt{x}$, $\sqrt{y^6} = y^3$.
So, $\sqrt{54x^3y^6} = 3 y^3 x \sqrt{6x}$.
11. Simplify $\sqrt{200ab^2}$.
$200 = 100 \times 2$, $\sqrt{100} = 10$.
$\sqrt{a} = \sqrt{a}$, $\sqrt{b^2} = b$.
So, $\sqrt{200ab^2} = 10 b \sqrt{2a}$.
12. Simplify $\sqrt{64a^6b}$.
$\sqrt{64} = 8$, $\sqrt{a^6} = a^3$, $\sqrt{b} = \sqrt{b}$.
Thus, $\sqrt{64a^6b} = 8 a^3 \sqrt{b}$.
13. Simplify $\sqrt[3]{1000x^6y^5}$.
$1000 = 10^3$, so $\sqrt[3]{1000} = 10$.
$\sqrt[3]{x^6} = x^{6/3} = x^2$.
$\sqrt[3]{y^5} = y^{1} \sqrt[3]{y^2} = y \sqrt[3]{y^2}$.
So, $\sqrt[3]{1000x^6y^5} = 10 x^2 y \sqrt[3]{y^2}$.
14. Simplify $\sqrt[4]{162x^2y^4z^6}$.
$162 = 81 \times 2$, $\sqrt[4]{81} = 3$ because $3^4=81$.
$\sqrt[4]{x^2} = x^{1/2} = \sqrt{x}$.
$\sqrt[4]{y^4} = y$.
$\sqrt[4]{z^6} = z^{6/4} = z^{3/2} = z \sqrt{z}$.
So, $\sqrt[4]{162x^2y^4z^6} = 3 y z \sqrt{x} \sqrt{z} \sqrt[4]{2}$.
15. Simplify $\sqrt[3]{128x^5y^4z^3}$.
$128 = 64 \times 2$, $\sqrt[3]{64} = 4$.
$\sqrt[3]{x^5} = x^{1} \sqrt[3]{x^2} = x \sqrt[3]{x^2}$.
$\sqrt[3]{y^4} = y \sqrt[3]{y}$.
$\sqrt[3]{z^3} = z$.
So, $\sqrt[3]{128x^5y^4z^3} = 4 x y z \sqrt[3]{2 x^2 y}$.
Final answers:
1. $2\sqrt{3}$
2. $7\sqrt{2}$
3. $11\sqrt{3}$
4. $6\sqrt{5}$
5. $5\sqrt{10}$
6. $2\sqrt[4]{3}$
7. $3\sqrt[5]{2}$
8. $2 x y \sqrt{y}$
9. $17 a^2 b$
10. $3 x y^3 \sqrt{6 x}$
11. $10 b \sqrt{2 a}$
12. $8 a^3 \sqrt{b}$
13. $10 x^2 y \sqrt[3]{y^2}$
14. $3 y z \sqrt{x} \sqrt{z} \sqrt[4]{2}$
15. $4 x y z \sqrt[3]{2 x^2 y}$