Simplify Radicals 2F54E9
1. **State the problem:** Simplify the expression $$7\sqrt{18x^2} + \sqrt{48x^4} + \sqrt{x^8}$$.
2. **Recall the square root properties:**
- $$\sqrt{a \cdot b} = \sqrt{a} \cdot \sqrt{b}$$
- $$\sqrt{x^n} = x^{\frac{n}{2}}$$ for $$x \geq 0$$.
3. **Simplify each term:**
- $$7\sqrt{18x^2} = 7 \cdot \sqrt{18} \cdot \sqrt{x^2} = 7 \cdot \sqrt{9 \cdot 2} \cdot x = 7 \cdot 3 \cdot \sqrt{2} \cdot x = 21x\sqrt{2}$$
- $$\sqrt{48x^4} = \sqrt{48} \cdot \sqrt{x^4} = \sqrt{16 \cdot 3} \cdot x^2 = 4x^2\sqrt{3}$$
- $$\sqrt{x^8} = x^{\frac{8}{2}} = x^4$$
4. **Rewrite the expression:**
$$21x\sqrt{2} + 4x^2\sqrt{3} + x^4$$
5. **Final answer:** The simplified form is $$21x\sqrt{2} + 4x^2\sqrt{3} + x^4$$.
This expression cannot be simplified further because the terms contain different radicals and powers of $$x$$.