1. **State the problem:** Simplify the expression $6\sqrt{3} - \sqrt{12} - \sqrt{48}$. 2. **Recall the rule:** $\sqrt{a \times b} = \sqrt{a} \times \sqrt{b}$, which helps simplify square roots by factoring out perfect squares. 3. **Simplify each square root:** - $\sqrt{12} = \sqrt{4 \times 3} = \sqrt{4} \times \sqrt{3} = 2\sqrt{3}$ - $\sqrt{48} = \sqrt{16 \times 3} = \sqrt{16} \times \sqrt{3} = 4\sqrt{3}$ 4. **Rewrite the expression:** $$6\sqrt{3} - 2\sqrt{3} - 4\sqrt{3}$$ 5. **Combine like terms:** $$ (6 - 2 - 4)\sqrt{3} = 0 \times \sqrt{3} = 0$$ 6. **Final answer:** $$0$$ The expression simplifies to zero, which corresponds to option ⓒ.