1. The problem is to create another example similar to a previous one, but since no specific problem was given, let's consider a simple algebra problem: Solve for $x$ in the equation $2x + 3 = 11$. 2. The formula used here is to isolate $x$ by performing inverse operations. Important rules: addition and subtraction undo each other, multiplication and division undo each other. 3. Subtract 3 from both sides: $$2x + 3 - 3 = 11 - 3$$ which simplifies to $$2x = 8$$ 4. Divide both sides by 2: $$\frac{2x}{2} = \frac{8}{2}$$ which simplifies to $$x = 4$$ 5. So, the solution is $x = 4$. This means when $x$ is 4, the original equation holds true.