1. The problem asks for the first three terms of the sequence defined by the nth term formula: $$a_n = 3 \times 2^{n-2}$$. 2. To find each term, substitute $n=1$, $n=2$, and $n=3$ into the formula. 3. Calculate the first term ($n=1$): $$a_1 = 3 \times 2^{1-2} = 3 \times 2^{-1} = 3 \times \frac{1}{2} = \frac{3}{2} = 1.5$$ 4. Calculate the second term ($n=2$): $$a_2 = 3 \times 2^{2-2} = 3 \times 2^{0} = 3 \times 1 = 3$$ 5. Calculate the third term ($n=3$): $$a_3 = 3 \times 2^{3-2} = 3 \times 2^{1} = 3 \times 2 = 6$$ 6. Therefore, the first three terms of the sequence are $1.5$, $3$, and $6$.