Sequence Position 6A9161
1. **State the problem:** We are given the nth term of a sequence as $$T(n) = 3n^2 + 8$$ and told that a term in this sequence has a value of 83. We need to find the position $$n$$ of this term.
2. **Write the equation:** Set $$T(n) = 83$$:
$$3n^2 + 8 = 83$$
3. **Solve for $$n$$:**
Subtract 8 from both sides:
$$3n^2 = 83 - 8$$
$$3n^2 = 75$$
Divide both sides by 3:
$$n^2 = \frac{75}{3} = 25$$
4. **Find $$n$$:**
Take the square root of both sides:
$$n = \pm 5$$
5. **Interpret the result:** Since $$n$$ represents the position in the sequence, it must be a positive integer. Therefore, $$n = 5$$.
**Final answer:** The term with value 83 is at position $$n = 5$$.